<p> (1)Δu=10.5-10=0.5(kV)<br> (2)设最大容量为S<br> 则,<img src="http://que-oss.fenziquan.com/web/akimg/asource/201505241434476775.jpg">(S)<br> (3)R=R<sub>0</sub>L=0.15×3=0.45(Ω)<br> X=X<sub>0</sub>L=0.34×3=1.02(Ω)<br> (4)<br> <img src="http://que-oss.fenziquan.com/web/akimg/asource/2015052414351831893.jpg"><br> ∴S<6.72(MVA)<br> (5)校验载流量<br> <img src="http://que-oss.fenziquan.com/web/akimg/asource/2015052414362465349.jpg"><br> =408(A)<br> LGJ-240导线在40℃室外温度时载流量为494>408,所以最大能送出6.72MVA。</p>