设总体X的分布密度φ（x；θ）为今从X中抽取10个个体，得数据如下：1 050，1 100，1 080，1 200，1 300，1 250，1 340，l 060，1 150，1 150。试用矩估计法估计θ。

<br>总体均值EX=<img src="/s/tiw/p3/UpLoadImage/2013-05-07/424c3de4-002e-44f6-b6e3-175e02349d05.png" width="93" height="35">=<img src="/s/tiw/p3/UpLoadImage/2013-05-07/094b2218-701e-4f36-a61d-6fdcd8bbb59c.png" width="69" height="41">=<img src="/s/tiw/p3/UpLoadImage/2013-05-07/2444ac1e-445f-48bd-8c53-d7cb291a1417.png" width="16" height="41"><br>由矩法估计得<img src="/s/tiw/p3/UpLoadImage/2013-05-07/2444ac1e-445f-48bd-8c53-d7cb291a1417.png" width="16" height="41">=<img src="/s/tiw/p3/UpLoadImage/2013-05-07/1767d575-d0a6-4620-a7d5-4157a5111b00.png" width="19" height="21">, <img src="/s/tiw/p3/UpLoadImage/2013-05-07/26ab6918-3cf1-4e35-86c4-40cb2952805e.png" width="47" height="43"><br>求得样本均值<img src="/s/tiw/p3/UpLoadImage/2013-05-07/1767d575-d0a6-4620-a7d5-4157a5111b00.png" width="19" height="21">=1168,所以<img src="/s/tiw/p3/UpLoadImage/2013-05-07/e89df646-fdec-44b1-8e6e-9c0a2a88f907.png" width="63" height="41">。