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12+22+32+…+1234567892的个位数是( )。
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12+22+32+…+1234567892的个位数是( )。
A、3
B、4
C、5
D、6
时间:2022-01-11 18:51
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江苏
广东
答案解析
C
原式各项的尾数按照12到92依次循环,则计算12+22+32+…+92的尾数即可,1+4+9+6+5+6+9+4+1的尾数为5,则所有数字之和的尾数为5。因此C项正确。
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